Question

x²-7x+9 வர்க்கங்களின் கூடுதல் காண்க.​

Answer 1

Answer:

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Answer 2

The roots of the given equation are $\alpha =\frac{49+\sqrt{13} }{2}$ and  $\beta =\frac{49-\sqrt{13} }{2}$

Explanation:

Given:

x²-7x+9

To find:

Roots of the equation

Formula:

$\alpha =\frac{-b+\sqrt{b^{2}-4ac } }{2a}$

$\beta =\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Solution:

==> From the equation x²-7x+9

==> a = Coefficient of x²

==> b = Coefficient of x

==> c = Constant

==> a = 1

==> b = -7

==> c = 9

==> Substitute the values in the formula

==> $\alpha =\frac{-b+\sqrt{b^{2}-4ac } }{2a}$

==> $\alpha =\frac{-(-7)+\sqrt{(-7)^{2}-4(1)(9) } }{2(1)}$

==> $\alpha =\frac{49+\sqrt{49-4(9) } }{2}$

==> $\alpha =\frac{49+\sqrt{49-36} }{2}$

==> $\alpha =\frac{49+\sqrt{49-36} }{2}$

==> $\alpha =\frac{49+\sqrt{13} }{2}$

==> Substitute the values in the formula

==> $\beta =\frac{-b-\sqrt{b^{2}-4ac } }{2a}$

==> $\beta =\frac{-(-7)-\sqrt{(-7)^{2}-4(1)(9) } }{2(1)}$

==> $\beta =\frac{49-\sqrt{49-4(9) } }{2}$

==> $\beta =\frac{49-\sqrt{49-36} }{2}$

==> $\beta =\frac{49-\sqrt{49-36} }{2}$

==> $\beta =\frac{49-\sqrt{13} }{2}$

The roots of the given equation are $\alpha =\frac{49+\sqrt{13} }{2}$ and  $\beta =\frac{49-\sqrt{13} }{2}$