Question

(x2 + 8x – 128) या राशीचे अवयव पुढीलपैकी कोणते​

Answer 1

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Answer 2

Answer:

Factoring x2-8x-128

The first term is, x2 its coefficient is 1 .

The middle term is, -8x its coefficient is -8 .

The last term, "the constant", is -128

Step-1 : Multiply the coefficient of the first term by the constant 1 • -128 = -128

Step-2 : Find two factors of -128 whose sum equals the coefficient of the middle term, which is -8 .

-128 + 1 = -127

-64 + 2 = -62

-32 + 4 = -28

-16 + 8 = -8 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -16 and 8

x2 - 16x + 8x - 128

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-16)

Add up the last 2 terms, pulling out common factors :

8 • (x-16)

Step-5 : Add up the four terms of step 4 :

(x+8) • (x-16)