Question

x²- 9 = (x+3) ( x-a) find the vale of a​

Answer 1

Answer:

x² - 9 = (x+3)(x-a)

(x+3)(x-3) = (x+3)(x-a)

x-3 = x-a

-a = -3

a = 3

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Answer 2

Answer:

3

Step-by-step explanation:

$x^2- 9 \\= x^2 + 3x - 3x - 9 \\= x(x + 3) -3(x + 3) \\= (x + 3)(x - 3)$

But according to the question:

$x^2- 9 \\= (x+3) ( x-a)$

So, (x +3)(x - 3) = (x + 3)(x -a)

=> x - 3 = x -a

=> a = 3