Question

x2-9x+20=0 factorise​

Answer 1

Answer:

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Step-by-step explanation:

${x}^{2} - 9x + 20 = 0 \\ {x}^{2} - 5x - 4x + 20 = 0 \\ x( {x} - 5) - 4(x - 5) = 0\\ (x - 4)(x -5 ) = 0 \\ x - 4 = 0 \: \: or \: \: x - 5 = 0 \\ x = 4 \: \: or \: \: x = 5$

Answer 2

Answer:

Step-by-step explanation:

$x^{2} -9x +20\\x^{2} -5x -4x +20\\x(x-5)-4(x-5)\\(x-4)(x-5)$

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