X2+9x+20 splitting the middle term
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x^2+9x+20
x^2 = 1x^2
multiply 20 and 1
ans= 20
factorise 20 in such a way that when factors of 20 is added their sum must be 9 ---> middle term
Then it will be like
x^2 + 5x + 4x + 20
Take out common terms
x(x+5) +4(x+5)
here↑ 5 is the factor of 20 = 5×4 ( 4 has been taken as common) next, take out x+4 and x+5
(x+4) (x+5)
steps will be
x^2 + 9x + 20
= x^2 +5x +4x + 20
= x(x+5) +4(x+5)
= (x+4) (x+5)
I know that these much big answers are not needed but this I think it will be more helpful for you
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