x²-9x+8 factorise by using identity
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x^2 - 8x - x + 8
= x ( x - 8 ) - 1 ( x - 8 )
= ( x - 1 ) ( x - 8 )
= x ( x - 8 ) - 1 ( x - 8 )
= ( x - 1 ) ( x - 8 )
Answered by
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x^2-9x+8=0
or,x^2-8x-x+8=0
or,x(x-8)-1 (x-8)=0
or, (x-8)(x-1)=0
x-8=0
x=8
and x-1=0
x=1
if it is helpful mark it as brainliest
or,x^2-8x-x+8=0
or,x(x-8)-1 (x-8)=0
or, (x-8)(x-1)=0
x-8=0
x=8
and x-1=0
x=1
if it is helpful mark it as brainliest
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