Question

x² in x/3(6x - (-1/-2). what will be the coefficient in this equation ?

Answer 1

Ans.

$\frac{x(6x - \frac{ - 1}{ - 2} )}{3} \\ = \frac{6 {x}^{2} - \frac{1}{2}x }{3} \\ = \frac{12 {x}^{2} - x}{6}$

You have written an expression.
But you asked answer for an equation.
So when, the term is made equal to 0, it becomes an equation :
$12 {x}^{2} - x = 0$
in which, the coefficient of
${x}^{2}$
is 12.

I HOPE THAT THIS HELPS YOU.