Question

x² + Kx + 20 Having equal
& equal roots find the value k​

Answer 1

x^+kx+20 comparing with ax^2+bx+c

a=1 b=k c=20

now,

b^2-4ac=0

k^2-80= 0

k^2= 80

k= √80

k=√16×5

k= 4√5