Question

x2-root3x+1=0 find the value of 2x3+2/x3

Answer 1

this is your answer

Step-by-step explanation:



ANSWER

Now, 3x2+x+5⩾0

This is because b2−4ac=1−4×5×3

=−59 (roots are imaginary)

3x2+x+5=(x−3)2=x2+9−6x and x−3⩾0

2x2+7x−4=0

2x2+8x−x−4=0

2x(x+4)−1(x+4)=0

(2x−1)(x+4)=0

x=21 and−4 but x≥3

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