x²+x+1=0,Find the discriminant of the given quadratic equations and discuss the nature of the roots.
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Given,
The equation is
![x {}^{2} + x + 1 = 0 x {}^{2} + x + 1 = 0](https://tex.z-dn.net/?f=x+%7B%7D%5E%7B2%7D+%2B+x+%2B+1+%3D+0)
Here,
a=1
b=1
c=1
•°• Discriminant is
![b {}^{2} - 4ac = 1 {}^{2} - 4.1.1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1 - 4 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 3 \: < 0 b {}^{2} - 4ac = 1 {}^{2} - 4.1.1 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 1 - 4 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = - 3 \: < 0](https://tex.z-dn.net/?f=b+%7B%7D%5E%7B2%7D+-+4ac+%3D+1+%7B%7D%5E%7B2%7D+-+4.1.1+%5C%5C+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%3D+1+-+4+%5C%5C+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%5C%3A+%3D+-+3+%5C%3A+%26lt%3B+0)
Hence the nature of roots are imaginary and unequal.
The equation is
Here,
a=1
b=1
c=1
•°• Discriminant is
Hence the nature of roots are imaginary and unequal.
mahir222:
hm
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