x²+(x+1)²=130 find zero
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Answer:
x=4
Step-by-step explanation:
x^2+(x+1)^2=130
x^2+x^2+1+2x=130
2x^2+2x=130
2x^2+1+2x=130
2x^2+1+x=130/2
2x^2+x=65-1
x^2+x=64
2x=√64
x=8/2
x=4
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