Question

x² + x +1
Resolve into partial fraction 7
on (x - 2)(x² - 4)​

Answer 1

Answer:

Step-by-step explanation:

Solution :

1/(x - 1) (x + 1) = A/(x - 1) + B/(x + 1)

1/(x - 1) (x + 1) = A(x + 1) + B(x - 1)/(x - 1)(x + 1)

Since we have same denominators on both side, we can equate the numerators.

1 = A(x + 1) + B(x - 1) ------(1)

The constants A and B can also be found by successively giving suitable values for x.

To find A, put x = 1 in (1)

To find B, put x = -1 in (1)

1 = A(1 + 1) + B(1 - 1)

1 = 2A + B (0)

1 = 2A + 0

2A = 1 ===> A = 1/2

1 = A(-1 + 1) + B(-1 - 1)

1 = A(0) + B (-2)

1 = 0 - 2B

-2B = 1 ===> B = -1/2

Answer 2

Step-by-step explanation:

x²

____________

(x-2)(x² -4)