(x2-x)2-8(x2-x)+12=0 solve given equation
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(x^2-x)2-8(x^2-x)+12=0
2x^2-2x-8x^2+8x+12=0
-6x^2+6x+12=0
6(-x^2+x+2)=0
-(x^2-x-2)=0
x^2-x-2=0
x^2-2x+1x-2=0
x(x-2)+1(x-2)
(x+1) and (x-2)
x=-1 and x=2
HOPE IT HELPS YOU...
(x^2-x)2-8(x^2-x)+12=0
2x^2-2x-8x^2+8x+12=0
-6x^2+6x+12=0
6(-x^2+x+2)=0
-(x^2-x-2)=0
x^2-x-2=0
x^2-2x+1x-2=0
x(x-2)+1(x-2)
(x+1) and (x-2)
x=-1 and x=2
HOPE IT HELPS YOU...
krishnajadhav:
^2 iska matlab square hai na
thank you
welcome
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