Question

(x2-x)2-8(x2-x)+12=0 solve given equation

Answer 1

ANSWER:-

(x^2-x)2-8(x^2-x)+12=0

2x^2-2x-8x^2+8x+12=0

-6x^2+6x+12=0

6(-x^2+x+2)=0

-(x^2-x-2)=0

x^2-x-2=0

x^2-2x+1x-2=0

x(x-2)+1(x-2)

(x+1) and (x-2)

x=-1 and x=2

HOPE IT HELPS YOU...