Math, asked by saish4171, 5 months ago

x²-x-3=0 please answer the question​

Answers

Answered by vivekpnair11479
0

Answer:

Hey gentleman,

Step-by-step explanation:

x^2-x-3=0

so,

x=-b +- root b^2 - 4ac/2a

x= 1 + (root13) / 2 and x = 1 - (root13) / 2

mark as brainliest!!!

Answered by 1994sitthiphorn
0

Answer:

x= (1+√13)/2 , (1-√13)/2

Step-by-step explanation:

x²-x-3 =0

a=1,b=-1,c=-3

from x = (-b ± √b²-4ac) / 2a

x= [-(-1) ± √(-1)²-4(1)(-3)] / 2(1)

= [1±√1+12] /2

= [1±√13] /2

x= (1+√13)/2 , (1-√13)/2

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