Question

(x²+x/6–1/6) Factorise​

Answer 1

Answer:

$\bf {x}^{2} + \frac{x}{6} - \frac{1}{6}$

Take LCM.

$\bf \implies \frac{1}{6} \times ( {6x}^{2} + x - 1)$

$\bf \implies \frac{1}{6} \times ( {6x}^{2} + 3x - 2x - 1)$

$\bf \implies \frac{1}{6} \times (3x(2x + 1) - 1(2x + 1))$

$\bf \implies \frac{1}{6} \times (3x - 1)(2x + 1)$

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Answer 2

Answer:

$\huge\underline\bold\red{Answer!!}$

$x {}^{2} + \frac{x}{6} - \frac{1}{6}$

Here L.C.M of denominator is 6:

$\frac{6 {x}^{2} + x - 1 }{6}$

Numerator can factorize by middle term splitting method:

$\frac{6x {}^{2} + 3x - 2x - 1 }{6}$

Taking common 3x in first and second term. Taking common -1 in third and fourth term of numerator:

$\frac{3x(2x + 1) - 1(2x + 1)}{6}$

$\frac{(3x - 1)(2x + 1)}{6}$

Above factorization can be written as :

$\frac{1}{6} \times (2x + 1) \times (3x - 1)$

hope it helps you ❤️ ✨