Question

X2+x/6-2 factorisation​

Answer 1

Step-by-step explanation:

$Given \ polynomial,\\ =>x^{2} +\frac{x}{6} -2 \\\\ => \frac{1}{6} [6x^{2} +x-12] \\\\ => \frac{1}{6} [6x^{2} +x-12] \\\\=> \frac{1}{6} [6x^{2} -8x+9x-12] \\\\=> \frac{1}{6} [2x(3x-4)+3(3x-4) ]\\\\=> \frac{1}{6} [(3x-4)(2x+3)]$