Question

-x²+x+6 find the root​

Answer 1

Answer:

$\huge\orange{-2 , 3}$

Step-by-step explanation:

According to the Q,

$> > - {x}^{2} + x + 6 = 0$

Sum = 1

Product = -1 x 6 = -6

$> > - {x}^{2} + 3x - 2x + 6 = 0$

$> > - x(x - 3) - 2(x - 3) = 0$

$> > ( - x - 2)(x - 3) = 0$

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$.°. (- x - 2 )= 0$

$> > - x = 2$

$\orange {> > x = -2}$

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$.°. (x - 3) = 0$

$\orange {> > x = 3}$

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Answer 2

$\tt\it\bf\it\bm{\mathcal{\fcolorbox{blue}{yellow}{\red{Solution:-}}}}$

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-x²+x+6=0

➡-1(x²-x-6)=0

➡x²-x-6=0

➡x²-3x+2x-6=0

➡x(x-3)+2(x-3)=0

➡(x-3)(x+2)=0

➡(x-3)=0 or (x+2)=0

➡x= 3 or x= -2

•°• $\tt{\red{ </strong><strong>x</strong><strong>=</strong><strong>3</strong><strong>\</strong><strong>:</strong><strong>or\</strong><strong>:</strong><strong>-</strong><strong>2</strong><strong> }}$

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