X²+x-(a+1)(a+2)=0 find the roots of the equation
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Hi there!
x² + x – (a + 2) (a + 1) = 0
⇒ x² + [(a + 2) – (a + 1)] x – (a + 2) (a + 1) = 0
⇒ x² + (a + 2) x – (a + 2) x – (a + 2) (a + 1) = 0
⇒ x [x + (a + 2)] – (a + 1) [x + (a + 2)] = 0
⇒ [x – (a + 1)] [x + (a + 2)] = 0
⇒ x – (a + 1) = 0 or x + (a + 2) = 0
⇒ x = a + 1 or x = – (a + 2)
Cheers!
x² + x – (a + 2) (a + 1) = 0
⇒ x² + [(a + 2) – (a + 1)] x – (a + 2) (a + 1) = 0
⇒ x² + (a + 2) x – (a + 2) x – (a + 2) (a + 1) = 0
⇒ x [x + (a + 2)] – (a + 1) [x + (a + 2)] = 0
⇒ [x – (a + 1)] [x + (a + 2)] = 0
⇒ x – (a + 1) = 0 or x + (a + 2) = 0
⇒ x = a + 1 or x = – (a + 2)
Cheers!
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