x2 - x - (a + 1)(a + 2) factorization of that math?
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Step-by-step explanation:
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Step-by-step explanation:
Given :-
x²-x-(a+1)(a+2)
To find :-
Factorise the given expression ?
Solution :-
Given expression is x² - x - (a+1)(a+2)
It can be written as
=> x² + (a+1)x - (a+2)x - (a+1)(a+2)
=> x[x+(a+1)] - (a+2)[x+(a+1)]
=>[x+(a+1)][x-(a+2)]
Therefore,
x²-x-(a+1)(a+2) = [x+(a+1)][x-(a+2)]
Answer:-
The factorization of the given expression is [x+(a+1)][x-(a+2)]
Used Method :-
→ Splitting the middle term
- Writing the given expression is
x²+(p+q)x+pq.
- x²+(p+q)x+pq = (x+p)(x+q)
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