Question

x²+ xy+8n+8y help me​

Answer 1

Answer:

Hello...

Here is your answer..

x² + xy + 8x + 8y

We observe that there is no common factor among all terms. Also, there are four terms.

So, let us think of grouping the terms in pairs in such a way that there are some factors common to them and after taking factors common from each pair same binomial is left inside the two brackets. We observe that first two terms have x as common factor. Taking x common from them, we have

x² + xy = x ( x + y )

Also, 8 is a common factor from the Last two terms. Taking 8 common from the last two terms, we have

8x + 8y = ( x + y)

Clearly, x + y is common from the two groups.

Thus, we group the two terms as follows :

x² + xy + 8x + 8y = (x² + xy) + (8x + 8y)

= x ( x + y) + 8 ( x + y)

= (x + 8) ( x + y)

Hope it helped ☺☺

Step-by-step explanation:

Answer 2

Answer:

I hope it help you..

have a great day ahead..