Question

x²-y²-1, y²-1-x², 1-x²-y²​

Answer 1

Answer:

Find `y(x)`, if it satisfies the following differential equation `(dy)/(dx)=(x-y)^2`, and given that `y(1)=1` (A) `-ln|(1-x+y)/(1+x-y)|=2(x-1)` (B) `ln|(2-y)/(2-x)=x+y-1` (C) `ln|(1-x+y)/(1+x-y)|=2(x-1)` (D) `1/2ln|(1-x+y)/(1+x-y)|+ln|x|=0`

Answer 2

Answer:

$-{x}^{2} - 1 - {y}^{2}$

Step-by-step explanation:

on adding it

hope its helpful m

mark brainliest