Question

x² + y² + 3x + 4y+1=0
2
Equation of circle passing through (-1,-2)
and concentric with the circle
1) x + y + 3x + 4y+6=0
2) x² + y2 – 3x - 4y+6=0
3) x + y + 3x + 4y -6=0
4) x² + y2 + 3x – 4y -6=0​

Answer 1

Answer:

Then point of intersections are given by

x

2

(1+m

2

)−x(3+4m)−4=0

∴x

1

+x

2

=

1+m

2

3+4m

and x

1

x

2

=

1+m

2

−4

Since (0,0) divides the chord in the ratio 1:4,

∴x

2

=−4x

1

−3x

1

=

1+m

2

3+4m

and 4x

1

2

=

1+m

2

−4

∴9+9m

2

=9+16m

2

+24m

i.e., m=0,−

7

24

Therefore, the lines are y=0 and 7y+24x=0.