Question

X2+y2 =41,x*y=20 find x and y values

Answer 1

x²+y²=41

xy=20

x²+2xy+y²= (x+y)² = 41+2(20) = 81.........(I)


x²-2xy+y²= (x-y)²= 41-2(20)=1............(ii)

(x+y)²=81

±(x+y)=9

x-y=1
solve these to get the ans