X2+y2 =41,x*y=20 find x and y values
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x²+y²=41
xy=20
x²+2xy+y²= (x+y)² = 41+2(20) = 81.........(I)
x²-2xy+y²= (x-y)²= 41-2(20)=1............(ii)
(x+y)²=81
±(x+y)=9
x-y=1
solve these to get the ans
xy=20
x²+2xy+y²= (x+y)² = 41+2(20) = 81.........(I)
x²-2xy+y²= (x-y)²= 41-2(20)=1............(ii)
(x+y)²=81
±(x+y)=9
x-y=1
solve these to get the ans
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