Math, asked by madhav4101, 1 year ago

X2+y2=61 & x3+y3=91
Find the value of x&y in the given equation?

Answers

Answered by AJThe123456
1
Heyy mate ❤✌✌❤

Here's your Answer.....

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x^2 + y^2 =61     x^3 - y^3=91
x^2=61- y^2
x=√61-y^2

Substitute in the second equation
x^3 - y^3=91​

(√61-y^2)^3-y^3=91

476.4 - y^3 - y^3 = 91

-2y^3 = -385.4

y^3 = 192.7

y = 5.7


Substituting the value of y in any one of the equations

x^2 + y^2 =61

x^2 +(5.7)^2 = 61

x^2=28.51

x=5.3
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madhav4101: thanks a lot for ur help
AJThe123456: wlcm
madhav4101: hey uh @AJThe123456 taken second equation wrong
Answered by Anjula
1
Hey !!!

Refer to the attachment !!
Attachments:

madhav4101: thanks but I have a doubt why uh taken x^3-y^3=91 as equation while in the question it is x^3+y^3=91
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