X2+y2=61 & x3+y3=91
Find the value of x&y in the given equation?
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Answered by
1
Heyy mate ❤✌✌❤
Here's your Answer.....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
x^2 + y^2 =61 x^3 - y^3=91
x^2=61- y^2
x=√61-y^2
Substitute in the second equation
x^3 - y^3=91
(√61-y^2)^3-y^3=91
476.4 - y^3 - y^3 = 91
-2y^3 = -385.4
y^3 = 192.7
y = 5.7
Substituting the value of y in any one of the equations
x^2 + y^2 =61
x^2 +(5.7)^2 = 61
x^2=28.51
x=5.3
✔✔✔
Here's your Answer.....
⤵️⤵️⤵️⤵️⤵️⤵️⤵️
x^2 + y^2 =61 x^3 - y^3=91
x^2=61- y^2
x=√61-y^2
Substitute in the second equation
x^3 - y^3=91
(√61-y^2)^3-y^3=91
476.4 - y^3 - y^3 = 91
-2y^3 = -385.4
y^3 = 192.7
y = 5.7
Substituting the value of y in any one of the equations
x^2 + y^2 =61
x^2 +(5.7)^2 = 61
x^2=28.51
x=5.3
✔✔✔
madhav4101:
thanks a lot for ur help
Answered by
1
Hey !!!
Refer to the attachment !!
Refer to the attachment !!
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