Math, asked by shrutigupta7799, 6 months ago

X²+y²-8x+6y+9=0, find the centre and the radius of this circle.

Answers

Answered by trupthi8
5

Complete the square for

x

and

y

and rearrange:

0

=

x

2

+

y

2

8

x

6

y

75

=

(

x

2

8

x

+

16

)

+

(

y

2

6

y

+

9

)

100

=

(

x

4

)

2

+

(

y

3

)

2

10

2

Add

10

2

to both ends and transpose to get:

(

x

4

)

2

+

(

y

3

)

2

=

10

2

This is in the standard form of the equation of a circle:

(

x

h

)

2

+

(

y

k

)

2

=

r

2

where

(

h

,

k

)

=

(

4

,

3

)

is the centre of the circle and

r

=

10

is the radius.

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