(x²-y²) (x4+x²y²+y²)
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1
Answer:
yes it's true
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4
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x4 + x2y2 + y4 = (x4 + 2x2y2 + y4) - x2y2 = (x2 + y2)2 – (xy)2, = [(x2 + y2) + xy] [(x2 + y2) – xy] = (x2 + xy + y2)(x2 –xy + y2)
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