(x²+z²-2xz)-y² how to factorize
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Answer:
(x-z)^2-(y)^2 =(x-z+y)(x-z-y)
Step-by-step explanation:
Firstly to factorise any given equation, Check whether it's in form of any identity or not so, here x^2+z^2-2xz is in form of (a-b)^2 = a^2-2ab+b^2.
so, we can write x^2+z^2-2xz as (x-z)^2
And then,(x-z)^2-(y)^2
If we see it carefully it also can be broken as (a+b)(a-b) as it's in form of a^2-b^2.
So, let a= x-z, b = y
Then, (x-z)^2-(y)^2 =(x-z+y)(x-z-y).
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