Question

X²yz-4xy³+20x³ find common factor

Answer 1

Answer:

The H.C.F. of numerical coefficients = The H.C.F. of 8, 12 and 20.

Since, 8 = 2 × 2 × 2 = 23, 12 = 2 × 2 × 3 = 22 × 31 and 20 = 2 × 2 × 5 = 22 × 51

Therefore, the H.C.F. of 8, 12 and 20 is 4

Now, the variables x and y are present in all the quantities. Out of these the highest common power of x is 2 and the highest common power if y is 1.

Therefore, the required H.C.F. = 4x2y1 = 4x2y

The method by which the H.C.F. of the monomials are determined can be formulated as follows:

(i) The H.C.F. of the numerical coefficients are to be determined at first.

(ii) Then the variables are to be written beside the coefficient with their highest common power or greatest common power.