Question

x³ – 1
solve it.....

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Answer 1

Answer:

x³ - 1 = 0

x³ = 1

(a - b)³ = a³ - b³ - 3ab(a-b)

So, there is no factoring polynomial.

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Hope it will be helpful :)

Answer 2

${x}^{3} - 1$

$( {x}^{3} - {1}^{3} )$

$= (x - 1)( {x}^{2} + (x)(1) + ( {1}^{2} )$

$= (x - 1)( {x}^{2} + x + 1)$

formula

• a³- b³= (a-b)(a² +ab +b²)