Math, asked by aryansth372, 2 days ago

x³+11x=6(x²+1) solve the following​

Answers

Answered by skdruv760
0

Answer:

((x3) + 11x) - 6 • (x2 + 1) = 0

STEP

2

:

Checking for a perfect cube

2.1 x3-6x2+11x-6 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3-6x2+11x-6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: 11x-6

Group 2: -6x2+x3

Pull out from each group separately :

Group 1: (11x-6) • (1)

Group 2: (x-6) • (x2)

Bad news !! Factoring by pulling out fails :

The groups have no common factor and can not be added up to form a multiplication.

Polynomial Roots Calculator :

2.3 Find roots (zeroes) of : F(x) = x3-6x2+11x-6

See theory in step 1.1

In this case, the Leading Coefficient is 1 and the Trailing Constant is -6.

The factor(s) are:

of the Leading Coefficient : 1

of the Trailing Constant : 1 ,2 ,3 ,6

Step-by-step explanation:

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