Question

X3 + 13 x2 + 32x+20factorise

Answer 1

Answer:

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Step-by-step explanation:

Let p(x) = x³+13x²+32x+20

p(-1) = -1+13-32+20= -33+33=0

Therefore (x+1) is a factor of p(x)

On dividing p(x) by (x+1) we get

p(x) ÷ (x+1) = x²+12x+20

Thus,

x³+13x²+32x+20 = (x+1) (x²+12x+20)

= (x+1) (x²+10x+2x+20)

= (x-1) [ x(x+10)+2(x+10)]

=(x-1) (x+2) (x+10)

Hence, x³+13x²+32x+20 = (x+1) (x+2) (x+10)