Question

x3+2x2-x-2:- factorise...​

Answer 1

★ FACTORISATION

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x³ - 2x² - x + 2

=> x²(x - 2) - 1(x - 2)

=> (x - 2)(x² - 1)

=> (x - 2){(x)² - (1)²}

=> (x - 2)(x - 1)(x + 1)

HOPE IT HELPS

Answer 2

Answer: Given that the equation is,

P(x)=x³+2x²-x-2

First put x=1

P(1)=1³+2-1-2=0

So p(1) is a zero of the polynomial...

Now by the trial and error method

1| 1 2. -1 -2

0 1 3 2

1 3 2 0

So, from this,

X²+3x+2=0

X²+2x+x+2=0

X(x+2)+1(x+2)=0

(x+1)(x+2)=0

X=-1,x= -2

So x values are 1,-1,-2...

Step-by-step explanation:

Hope it helps you frnd......

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