Math, asked by arathivinod7667, 1 month ago

x³ - 3 cotx +5√x find the derivative w.r.t.x

Answers

Answered by sanchghosh9
0

Answer:

y=x^3-3cot +5√x

dy /dx =3x²+3cosec ²x+5/(2√x)

Answered by vipinkumar212003
0

Answer:

 {x}^{3}  - 3 \cot x + 5 \sqrt{x}  \\  = {x}^{3}  - 3 \cot x + 5  {x}^{ \frac{1}{2} }  \\  \color{blue}{ \underline{differentiate \: w.r.t \: x}} \\ \frac{d({x}^{3}  - 3 \cot x + 5  {x}^{ \frac{1}{2} }) }{x}   \\  \\  =  \frac{d( {x}^{3} )}{dx}  - \frac{d( 3 \cot x )}{dx} + \frac{d( 5 {x}^{ \frac{1}{2} }  )}{dx} \\   \\ = 3 {x}^{2}  - 3 \times ( -  { \cosec}^{2} x) + 5 \times  \frac{1}{2}  {x}^{ -  \frac{1}{2} }  \\  \\  = 3 {x}^{2}  + 3 { \cosec}^{2} x +  \frac{5}{2 \sqrt{x} }  \\  \\\red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}

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