Question

x³-3x+2 solve this equation
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Answer 1

Answer:

Question:-

$\bf \: Solve \: the \: equation: {x}^{3 } - 3x + 2 = 0$

Answer:-

$\large{\boxed{\boxed{\bf{Solution}}}}$

$\bf \: {x}^{3} - 3x + 2 = 0$

$\bf\implies \: {x}^{3} - x - 2x + 2 = 0$

$\bf\implies \:x( {x}^{2} - 1) - 2(x - 1) = 0$

$\bf\implies \:x(x - 1)(x + 1) - 2(x - 1) = 0$

$\bf\implies \:(x - 1)(x(x + 1) - 2) = 0$

$\bf\implies \:(x - 1)( {x}^{2} + x - 2) = 0$

$\bf\implies \:(x - 1)( {x}^{2} + 2x - x - 2) = 0$

$\bf\implies \:(x - 1)(x(x + 2) - 1(x + 2)) = 0$

$\bf\implies \:(x - 1)(x + 2)(x - 1) = 0$

$\bf\implies \:x = 1 \: or \: x = - 2$

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