x³-6x²+10x-2 is divided by x²-5x+6that equal to f(x)+Adivided by x-2 B divided by x-3 then f(x) is?
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Answer:
Constant term =10
Possible factors of 10=+/-1,+/-2,+/-5,+/-10
P(x)=x^3–6x^2+3x+10
P(-1)=(-1)^3–6(-1)^2+3(-1)+10
=>-1–6–3+10=-10+10=0 gives
(x+1) is a factor of P(x).
=>x^3+x^2–7x^2–7x+10x+10
=>x^2(x+1)-7x(x+1)+10(x+1)
=>(x+1)(x^2–7x+10)
Using split middle term
=>(x+1){(x^2-(5+2)x+10}
=>(x+1){x(x-5)-2(x-5)}
=>(x+1)(x-5)(x-2)
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