x³-6x²+11x-6 factorize the polynomial
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gautam3175:
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Given (x^3)-6(x^2)+11x-6=0
let x=1 is the factor of the equation
1 |1 -6 11 -6
| 0 1 -5 6
-----------------------
1 -5 6 0
hence x=1 is one of the factor
=>x^2-5x+6=0
=>x^2-2x-3x+6=0
=>x(x-2)-3(x-2)=0
=>(x-2)(x-3)=0
hence factor are (x-1)(x-2)(x-3)=0
let x=1 is the factor of the equation
1 |1 -6 11 -6
| 0 1 -5 6
-----------------------
1 -5 6 0
hence x=1 is one of the factor
=>x^2-5x+6=0
=>x^2-2x-3x+6=0
=>x(x-2)-3(x-2)=0
=>(x-2)(x-3)=0
hence factor are (x-1)(x-2)(x-3)=0
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