Question

X³+qx²+px+6 factor is (x+1)and(x-2)

Answer 1

Here,

${x}^{3} + q {x}^{2} + px + 6 = 0$
Again,
x+1=0 and x-2 = 0
=> x=-1,2

for x=-1
${ - 1}^{3} + { - 1}^{2} q + p \times - 1 + 6 = 0 \\ = > - 1 + q - p + 6 = 0 \\ = > p - q = 0 \\ = > p = q$











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