Math, asked by Anonymous, 4 months ago

x³+x²-10x+8 divide by x-2 by division theorem​

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Answered by Anonymous
2

Answer:

p(x) =  {x}^{3}  +  {x}^{2} - 10x + 8  \\ p(2) =  {(2)}^{3}  +  {(2)}^{2}  - 10 \times 2 + 8 \\ p(2) = 8 + 4 - 20 + 8 \\ p(2) = 12 - 12 \\ p(2) = 0

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