Question

x3+x2+x+1 is divided by x-1/2 what is the remainder

Answer 1

According to given sum,

${x}^{3} + {x}^{2} + x + 1$
By remainder theorem,

x-1/2=0
x=1/2

Replace the x with 1/2 in the polynomial.

${x}^{3} + {x}^{2} + x + 1$

$( { \frac{1}{2} })^{3} + ( { \frac{1}{2} })^{2} + \frac{1}{2} + 1$

$\frac{1}{8} + \frac{1}{4} + \frac{1}{2} + 1$

$\frac{1 + 2 + 4 + 8}{8}$

$= \frac{15}{8}$

Hence remainder is 15/8.

:-)hope it helps u.

Answer 2

Answer is 15/8........