x3+y3=3axy find dy/dx
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differentiate equation w.r.t. x
we get
3x2+3y2*dy/dx= 3a(y+x*dy/dx)
dy/dx(3y2-3ax)=3ay-3x2
dy/dx= (3ay-3x2)/(3y2-3ax)
we get
3x2+3y2*dy/dx= 3a(y+x*dy/dx)
dy/dx(3y2-3ax)=3ay-3x2
dy/dx= (3ay-3x2)/(3y2-3ax)
vikashbirua8367:
thanks
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