x3+y3+z3+-3xyz when x=2 ,y=1,z=-3
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See, x=2, y=1, z=-3
Let's substitute the values in the equation
x3+y3+z3-3xyz
We get,
=(2)3 + (1)3+(-3)3 - 2(-3)3
=8+1-27+18
=27-27
=0
Hope it helped,
Mark as brainliest if it did
Let's substitute the values in the equation
x3+y3+z3-3xyz
We get,
=(2)3 + (1)3+(-3)3 - 2(-3)3
=8+1-27+18
=27-27
=0
Hope it helped,
Mark as brainliest if it did
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