x³+y³+z³=8?
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Answer:
There are different possibilities
Step-by-step explanation:
When x=2, y=0,z=0 :
2³+0³+0³=8
There are hundreds of possibilities ie when x and y are corresponding positive and negative integers and z remains 2.. For eg:-
When x= 1, y=-1, z= 2, then again
1³+(-1)³+2³=8
1-1+8 = 8
8=8
When x= 3, y=--3, z= 2, then again
3³+(-3)³+2³=8
27-27+8 = 8
8=8
When x= 4, y=-4, z= 2, then again
4³+(-4)³+2³=8
64-64+8 = 8
8=8
There are Millions of combinations like this.....
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