x⁴+1/x⁴+1 factorise it
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Answer:
[x²-(√3i-1)/2x²] [x²+(√3i+1)/2x²]
Step-by-step explanation:
= x⁴ + 1/x⁴ +1
= (x²)²+ (1/x²)²+ (x²)(1/x²)
let Y = x² and c = 1/x²
= y²+ c² + cy
using roots of a quadratic equation formula,
X = [-b±√(b²-4ac)]/2a
y = [-c ±√(c²-4(c²))]/ 2
= [-c ±√(-3c²)]/2
= (-c ±√3 c i)/2
so, equation is now = [y-(c(√3i-1)/2] [y+(c(√3i+1)/2]
= [x²-(√3i-1)/2x²] [x²+(√3i+1)/2x²]
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