x4 - 25x² + 144 = 0 solve quadritic equation
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Step-by-step explanation:
Given:-
x^4 - 25x^2 + 144 = 0
To find:-
Solve the equation ?
Solution:-
Given equation is x^4 - 25x^2 + 144 = 0
It can be written as is x^4 - 16x^2-9x^2 + 144 = 0
=>x^2(x^2-16)-9(x^2-16) = 0
=>(x^2-16)(x^2-9)=0
=>(x^2-4^2)(x^2-3^2)=0
We know that a^2-b^2 = (a+b)(a-b)
=>(x+4)(x-4)(x+3)(x-3) = 0
=>x+4 = 0 or x-4=0 or x+3 = 0 or x-3 = 0
=>x = -4 or 4 or -3 or 3
therefore,x = -4 , 4 , -3 ,3
Solution:-
The roots of the given equation are -4, -3, 3, 4
Additional information:-
- An equation of the degree 4 is called bi-quadratic equation.
- It has at most 4 roots.
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