x⁶-27, Factorize the given equation.
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(x^2)^3 - (3)^3
{(x^2)-3}{(x^2)^2+3x^2+9}
[x^2-3][x^4+3x^2+9]
{(x^2)-3}{(x^2)^2+3x^2+9}
[x^2-3][x^4+3x^2+9]
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Answer:
x^6 - 27
= ( x² - 3 )( x⁴ + 3x² + 9 )
Step-by-step explanation:
********************************
We know the algebraic identity :
a³ - b³ = ( a - b )( a² + ab + b² )
**************************************
x^6 - 27
= ( x² )³ - 3³
= ( x²-3 )[ (x²)²+(x²)×3 + 3² ]
= ( x² - 3 )( x⁴ + 3x² + 9 )
••••
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