Question

x⁶-27, Factorize the given equation.

Answer 1

(x^2)^3 - (3)^3
{(x^2)-3}{(x^2)^2+3x^2+9}
[x^2-3][x^4+3x^2+9]

Answer 2

Answer:

x^6 - 27

= ( x² - 3 )( x⁴ + 3x² + 9 )

Step-by-step explanation:

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We know the algebraic identity :

a³ - b³ = ( a - b )( a² + ab + b² )

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x^6 - 27

= ( x² )³ - 3³

= ( x²-3 )[ (x²)²+(x²)×3 + 3² ]

= ( x² - 3 )( x⁴ + 3x² + 9 )

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