(xa/xb) a+b-c (xb/xc) b+c-a (xc/xa) c+a-b show that RHS=LHS
Answers
Answered by
3
Answer:
L.H.S. = (xa/xb)1/ab (xb/xc)1/bc (xc/xa)1/ca
= (x a-b)1/b (xb-c)1/bc (xc-a)1/ca
= x a-b/ab xb-c/bc x c-a/ca
{(xa)b = xab}
= x a-b/ab + b-c/bc +c-a/ca
= x (ac – bc + ab – ac + bc – ab)/abc
= x0 = 1 = R.H.S (∵XO = 1)
Similar questions