Question

Xavier throws two fair dice together. What is the probability of scoring: (i) no fours?

Answer 1

Hi friend,

The possible outcomes when a dice is thrown are (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

The no.of possible outcomes are 36.

What is the probability of scoring no fours?
The favourable outcomes are (1,1)(1,2)(1,3)(1,5)(1,6)(2,1)(2,2)(2,3)(2,5)(2,6)(3,1)(3,2)(3,3)(3,5)(3,6)(5,1)(5,2)(5,3)(5,5)(5,6)(6,1)(6,2)(6,3)(6,5)(6,6)

The no.of favourable outcomes are 25

So, probability =25/36

hope it helps