Chemistry, asked by durgaray2002, 10 months ago

XeF6 +H,0 =
XeOFq + 2HF constant = K,, XeO4 + XeF
XeOFq + XeO, F, constantă
XeO,F2 + H2O will be
K2. Then equilibrium constant for the reaction XeO, + 2HF
Ki
K₂
K,
(4) (K₂²
(3) K
(1) K2
(2) K, + K​

Answers

Answered by priya1519
19

Explanation:

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