Math, asked by cnu506221, 2 days ago

xex as x varies from x=1 to x=3​

Answers

Answered by SLAABYBGAMINGB
0

Answer:

13.3995

Step-by-step explanation:

The average value of a continuous function

F

over an interval

[

a

,

b

]

is

1

b

a

b

a

F

(

x

)

d

x

.

For

F

(

x

)

=

x

e

x

2

over the interval

[

0

,

2

]

, this becomes

1

2

2

0

x

e

x

2

d

x

The integral can be done using the substitution

u

=

x

2

, making

d

u

=

2

x

d

x

. Also, when

x

=

0

,

u

=

0

and when

x

=

2

,

u

=

2

2

=

4

. Therefore, the quantity above can be written as

1

2

4

0

1

2

e

u

d

u

=

[

1

4

e

u

]

4

0

=

1

4

e

4

1

4

e

0

=

1

4

e

4

1

4

13.3995

Answered by sj46165440
0

Correct option is B)

y=x+

x

1

dx

dy

=(1−

x

2

1

)=

x

2

x

2

−1

for criticla point

x

2

x

2

−1

=0

or x=−1,+1

at x=−1, as f

(x) changes from +ve to −ve by going left to right, it is a point of local maxima

and f(−1)=−1+

−1

1

=−2

at x=+1, on f

(n) changes from −ve to +ve by going left to right, if n a point of local minima.

and f(1)=1+

1

1

=2

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