(xiii) 8a4 + 2a? - 45 please
Answers
Answered by
0
Answer:
grugcfjvgkgvdjogtsjecjsv
Answered by
1
Step-by-step explanation:
8a4 + 2a2-45
=8a4 + 20a2- 18a2-45
=4a2(2a2 + 5)-9(2a2 + 5)
=(4a2-9)(2a2 + 5)
Apply the formula a2 – b2 = (a-b) (a+b) in(4a2-9)
(4a2-9)= ((2a)2 – 32)
= (2a-3)(2a+3)
So,
8a4 + 2a2-45 = (2a2 + 5) (2a-3)(2a+3)
∴ the factors of 8a4 + 2a2-45 are (2a2 + 5) (2a-3)(2a+3)
Similar questions